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Slope of lines: Created from points at Basic Diameters

wrangler325
Team,

I'm having trouble with Slope of lines created from points at Basic diameters. The picture shows 4 points ( E,F,G AND H ) all located on Basic diameters. The slope call out appears to be asking slope of each line to Datum -A-, which is the top plane, Z axis of part. I have taken these points at the specified basic diameters, created lines from these points, but the results are 0.297 inches. I know I'm doing something wrong.
Any help is appreciated. Will provide more info if needed.
Greg.




Slope issue picture.pdf
Parents
  • Have attached a pdf sketch showing how to obtain the angles using some simple TRIG.


    Or you could create the points and get the angles by.

    Create 2 generic circles of 8.880 and 7.260 and a generic X vector line

    Intersect the line with the 7.260 circle to obtain Point 'E'

    Set origin on the point

    Create a generic line X,Y Zero with vectors of I -0.017452, J 0.99984769, K0.0 0

    Intersect line with the 8.880 circle to obtain Point 'F'





    Attached Files
  • in reply to UKCMM
    You don't. The slope is covered by the profile tolerance and according to your sketch, basic (or TED) so that shouldn't (in my opinion) be reported. It is there so you can calculate the position of the surface (like I did). If you'd had a CAD that worked, you'd simply click a point on that slope and everything (values, theos) would be taken from the CAD. No manual calculation (headache) needed.
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  • in reply to UKCMM
    You don't. The slope is covered by the profile tolerance and according to your sketch, basic (or TED) so that shouldn't (in my opinion) be reported. It is there so you can calculate the position of the surface (like I did). If you'd had a CAD that worked, you'd simply click a point on that slope and everything (values, theos) would be taken from the CAD. No manual calculation (headache) needed.
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