JacobCheverie :
I saw that the form was (a+b)^n-(a-b)^n, so each even value of n eliminates a^n and b^n, and odd values eliminates a^n and ab products with b^(even number)
n=1 function = 2b
n=2 function = 4ab
n=3 function =6a^2b+2b^3
Then, using the right formula is a good help !
JacobCheverie :
I saw that the form was (a+b)^n-(a-b)^n, so each even value of n eliminates a^n and b^n, and odd values eliminates a^n and ab products with b^(even number)
n=1 function = 2b
n=2 function = 4ab
n=3 function =6a^2b+2b^3
Then, using the right formula is a good help !
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