Looking for some help with the 1.839/1.849 distance. This callout is not a Cartesian distance . Its asking for the circumference value from point to point. I'm thinking this is going to need some combination of variables. Using 2015.1 CAD. Thanks!
Just to be difficult..... What if the diameter is significantly out of round?
Like Dph51 said, scan with a little distance between hits, then :
ASSIGN/V1=SCN1.HIT[1..(SCN1.NUMHITS-1)].XYZ
ASSIGN/V2=SCN1.HIT[2..SCN1.NUMHITS].XYZ
ASSIGN/V3=SUM(SQRT(DOT(V2-V1,V2-V1)))
ASSIGN/V4=SQRT(DOT(SCN1.HIT[SCN1.NUMHITS].XYZ-SCN1.HIT[1].XYZ,SCN1.HIT[SCN1.NUMHITS].XYZ-SCN1.HIT[1].XYZ))
ASSIGN/LENGTH=V3+V4
The uncertainty on this method should be approximately half of the density of the scan.
Just to be difficult..... What if the diameter is significantly out of round?
Like Dph51 said, scan with a little distance between hits, then :
ASSIGN/V1=SCN1.HIT[1..(SCN1.NUMHITS-1)].XYZ
ASSIGN/V2=SCN1.HIT[2..SCN1.NUMHITS].XYZ
ASSIGN/V3=SUM(SQRT(DOT(V2-V1,V2-V1)))
ASSIGN/V4=SQRT(DOT(SCN1.HIT[SCN1.NUMHITS].XYZ-SCN1.HIT[1].XYZ,SCN1.HIT[SCN1.NUMHITS].XYZ-SCN1.HIT[1].XYZ))
ASSIGN/LENGTH=V3+V4
The uncertainty on this method should be approximately half of the density of the scan.
