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Composite Tolerance



I am having trouble understanding composite tolerance, especially when it comes to a bolt hole pattern like this. I am wondering how you would dimension these true positions. Here's my idea using legacy dimensioning:

Level and translate to A, rotate to B, and report the position of 1 hole (any hole?...lets say the 12'O'Clock hole) and give it a .001 tolerance. Then, would I stay leveled to A&B, translate to the hole that I just reported on (12'O'Clock hole), and report the positions of the rest of the holes with a .0005 tolerance?​

Thanks so much...I prefer to use legacy...
Parents
  • So, our shelf has 10 mm holes in it and we've improved our drawing to include MMC for the features. We want hard gages for this because, while business is good, we can't yet afford a CMM

    For the top segment, the gage would be 3 mutually perpendicular planes. In datum A there would be 2 pins with a diameter of 5 mm. Pins would be located as close as the toolmaker can place them to the holes basic dimensions.

    Middle segment gage would have 2 perpendicular planes at -A- and -B-. Datum A would still have 2 pins at their Basic location, but now the diameter would be 8 mm.

    Bottom segment gage is a single plane, again with two pins, but now the Pin diameter is 9.5 mm.

    This setup makes sense to me.

    However, I'm having trouble trying to imagine a hard gage that fulfills both segments of the callout in the original post. Gage would have to make contact with both -A- and -B- with a chuck to restrain -A- while holding the part against -B-. Assuming that the position should be at MMC, the Top segment pin size would be .001 smaller than the smallest allowable hole size. Bottom segment pin should be .0005 smaller than the smallest allowable hole size.

    I don't see how the lower segment is refining the relationship of the holes.

    Not trying to be difficult here, just trying to understand the logic.​
Reply
  • So, our shelf has 10 mm holes in it and we've improved our drawing to include MMC for the features. We want hard gages for this because, while business is good, we can't yet afford a CMM

    For the top segment, the gage would be 3 mutually perpendicular planes. In datum A there would be 2 pins with a diameter of 5 mm. Pins would be located as close as the toolmaker can place them to the holes basic dimensions.

    Middle segment gage would have 2 perpendicular planes at -A- and -B-. Datum A would still have 2 pins at their Basic location, but now the diameter would be 8 mm.

    Bottom segment gage is a single plane, again with two pins, but now the Pin diameter is 9.5 mm.

    This setup makes sense to me.

    However, I'm having trouble trying to imagine a hard gage that fulfills both segments of the callout in the original post. Gage would have to make contact with both -A- and -B- with a chuck to restrain -A- while holding the part against -B-. Assuming that the position should be at MMC, the Top segment pin size would be .001 smaller than the smallest allowable hole size. Bottom segment pin should be .0005 smaller than the smallest allowable hole size.

    I don't see how the lower segment is refining the relationship of the holes.

    Not trying to be difficult here, just trying to understand the logic.​
Children