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Calculating true position using bonus tolerance

I'm running a program that I am reporting out true position for three holes. If you look at the report, it is showing them out of tolerance, but it doesn't look like it is using the bonus tolerance. I calling out the true position to three datums. Primary datum (A) is a plane, secondary datum (B) is a diameter, tertiary datum (C) is another diameter perpendicular to the secondary datum (I constructed a line between the two and rotated to that in my alignment). The print calls out MMC on the feature itself, as well as MMC on B and C. I looked online to see if I could find a math formula to double check PC-DMIS's report output, but I couldn't find any that used three datums. Does anyone know it? Does the report look like it calculated correctly?
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  • If you look at the bonus, it appears that you have a bonus of 0.0005. However, you are OOT by 0.0077.

    Generic formula 2*sqrt(x-meas^2+z-meas^2)

    For a formula(using 10 o'clock hole). 2*sqrt( 0.0011^2+0.0037^2) This would be correct.

    The bonus tolerance would be the 0.0005 given for the size modification of the diameter(0.0050-0.0045)
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  • If you look at the bonus, it appears that you have a bonus of 0.0005. However, you are OOT by 0.0077.

    Generic formula 2*sqrt(x-meas^2+z-meas^2)

    For a formula(using 10 o'clock hole). 2*sqrt( 0.0011^2+0.0037^2) This would be correct.

    The bonus tolerance would be the 0.0005 given for the size modification of the diameter(0.0050-0.0045)
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