Just curious on how you would dimension the lower portion of the FCF. The 1 mm to itself, it should simulate a hand apply. I have done it different ways to see the results. I normally set the origin in one feature and dimension the other feature, since they are to themselves. If I line up the two features, one axis is zero, I could accept that. Cannot use a set of features, that is to the datum scheme -ABC-. I just want to know how others would dimension the callout; I am using legacy. Thanks in advance.
As usual genius engineers put things on the print without fully understanding what they are really doing. I was once told if you have a lower portion of the FCF set up like this the holes are required to be located with respect to each other so my guess is set origin in one hole & dimension the next hole. Then repeat this using that second hole as origin.
As usual genius engineers put things on the print without fully understanding what they are really doing. I was once told if you have a lower portion of the FCF set up like this the holes are required to be located with respect to each other so my guess is set origin in one hole & dimension the next hole. Then repeat this using that second hole as origin.
