Is it possible to fetch a variable value which is referenced by other variable ?

Hi,

As per below code, I have created variables (body_1, body_2) using other variable's string values (body). Now I want to access "body_1" in my code but I suspect it is possible to access it.

_________________________________________________________

var set var = $_self.part_name string = &

"body", &

"subframe", &

"upright"

var set var = (eval("$_self."//($_self.part_name[1]))) string = &

"body_1", &

"body_2", &

var set var = (eval("$_self."//($_self.part_name[2]))) string = &

"subframe_1", &

"subframe_2", &

var set var = (eval("$_self."//($_self.part_name[3]))) string = &

"upright_1", &

"upright_2", &

acar too mess mess=(eval($_self.part_name[1].string_value[1]))

_____________________________________________________________________

Regards,

Darshan M. Vachhani

AF Consult, Sweden

Parents

0 darshan.v over 7 years ago

Hi Rishi,

Thank you for the reply.

Actually I want to access values of variables which is created by other variable names.

In my example code, I want to access "body_1" through the variable "$_self.part_name" which I have created in the beginning.

BTW, I got the resolution as below. May be not proper but it works for me.

acar too mess mess=(eval(STOO("$_self."//($_self.part_name[1])).string_value[1]))

acar too mess mess=(eval(STOO("$_self."//($_self.part_name[1])).string_value[2]))

This gives output as,

body_1

bosy_2

Thank you.

Regards,

Darshan M. Vachhani

AF Consult, Sweden
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0 darshan.v over 7 years ago

Hi Rishi,

Thank you for the reply.

Actually I want to access values of variables which is created by other variable names.

In my example code, I want to access "body_1" through the variable "$_self.part_name" which I have created in the beginning.

BTW, I got the resolution as below. May be not proper but it works for me.

acar too mess mess=(eval(STOO("$_self."//($_self.part_name[1])).string_value[1]))

acar too mess mess=(eval(STOO("$_self."//($_self.part_name[1])).string_value[2]))

This gives output as,

body_1

bosy_2

Thank you.

Regards,

Darshan M. Vachhani

AF Consult, Sweden
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