BASIC DIMENSIONS USE G D &T TOLERANCING, THE QUESTION IS I HAVE BASIC DIMENSIONS COMING FROM X & Y AXIS. AM I SUPPOSED TO "CUT" THE TOLERANCE IN HALF WHEN DIMENSIONING THE BASIC DIMENSION? example X AND Y ARE BOTH [2.077] THE TRUE POSITION CALLOUT IS ALLOWING UP TO .015 SHOULD I USE .0075 FOR X AND .0075 FOR MY Y TOLERANCE?
You obviously have no idea about how basic dimensions work (or even that there is a button marked 'caps lock' on your keyboard...), so I'll give you the advice that I nearly always give those who either can't or don't understand the mathematical theory behind it:
Take your "true position" value, and divide by 1/3 for the safe amount of tolerance in either direction. This will in effect be over-tolerancing the position, but will keep even the least experienced operator safe from creating scrap.
This is far better, and correct.
There is a correct mathematical formula for calculating true position RFS. Simple and quick. Square deviation of X and Y, add them together, take the square root of that number and multiply that by 2. That would be the formula you give your operator.
NUGUY,
Thank you for supplying the correct information to someone that is learning.
Much better than teaching them an incorrect method that they'll start using and be embarassed when someone calls them out.
All of us were new at one time or another. Someone taught us.
It's our obligation to teach others.
You obviously have no idea about how basic dimensions work (or even that there is a button marked 'caps lock' on your keyboard...), so I'll give you the advice that I nearly always give those who either can't or don't understand the mathematical theory behind it:
Take your "true position" value, and divide by 1/3 for the safe amount of tolerance in either direction. This will in effect be over-tolerancing the position, but will keep even the least experienced operator safe from creating scrap.
This is far better, and correct.
There is a correct mathematical formula for calculating true position RFS. Simple and quick. Square deviation of X and Y, add them together, take the square root of that number and multiply that by 2. That would be the formula you give your operator.
NUGUY,
Thank you for supplying the correct information to someone that is learning.
Much better than teaching them an incorrect method that they'll start using and be embarassed when someone calls them out.
All of us were new at one time or another. Someone taught us.
It's our obligation to teach others.
