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Quick question About ISO.....

If a Blueprint calls for ASME Y14.5 wouldn't this be the standard rules apply. How would I know if and when to apply ISO? I have yet to see anything on a blueprint stating this. The reason I bring this up is for the good old Profile callout. Before I make an argument, I want to cover all my resources. Customer already claims in an email that PC-DMIS is not capable of doing this. I and everyone on here already that's horse_S_H_I_T. But its Friday and I'm ready to P_I_S_S someone off
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  • {"data-align":"none","data-size":"large","data-attachmentid":400499} , an update for you guys to help us all understand ASME a little better. This is ASME Y14.5.1M-1994 Mathematical Definition of Dimensioning and Tolerancing Principles. {"data-align":"none","data-size":"large","data-attachmentid":400500}


    Thanks . That's in a separate publication from the standard itself isn't it?
    If I understand that correctly, that is a description of how it is to be toleranced right?
    So that if it is bi-lateral, the tolerance is the sum of the positive and negative sides of the tolerance.
    If it were unilateral, the tolerance would be just the one side.
    So that's still not saying how it should be reported right? The controversy is still open to rage on... Confounded
  • I'll post more on unilateral from the book tomorrow. I was just showing this to help everyone on this matter. That's what the forum is for. I worked with a machinist who used to use the X2 thing. But his reasoning was since he wasn't in a temperature controlled room. This would give him worst case condition. Because of expansion of metal from hot to cold.
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  • I'll post more on unilateral from the book tomorrow. I was just showing this to help everyone on this matter. That's what the forum is for. I worked with a machinist who used to use the X2 thing. But his reasoning was since he wasn't in a temperature controlled room. This would give him worst case condition. Because of expansion of metal from hot to cold.
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