hexagon logo

Iterative alignment and using XactMeasure

Alright here is my problem/question.
I have a part where Datum -A- (Z axis) is not prismatic, however datum -B- (X axis) and -C- (Y axis) are.

I do not have much experience with Iterative alignments other than that I have been to the Level 2 Hexagon class (Just don't use them or have the need too).

My thoughts were, this is a good time, to try an Iterative alignment.
I believe I have that part of the program correct:
I created 6 auto vector points on top (Datum -A-),
then 5 auto vector points on left side (Datum -B-)
then finally 5 auto vector points on the front of the part (Datum -C-).

When I create the Iterative alignment I pick top 6 points as level (Datum -A-),
5 points on left rotate (Datum -B-),
then 5 points on front as origin (Datum -C-).

After completing this Iterative alignment my trihedron doesn't move from before the alignment.
So I constructed planes out of the five points for datum -B- and -C- respectively.
I then origin my "X" to Datum -B- and my "Y" to datum -C-.
How do I origin my "Z", and how do I assign my datum -A- for exact measure? Where did I go wrong? Please any help would be greatly appreciated.
Parents
  • Call it rude, call it whatever you want.

    You've been given ALL the (correct) answers, if you can't make heads or tails of it, then "chatting" on the webs won't solve it, you need classroom training.

    If you are aligned to the "A" datum (321 or iterative), any dimension created after the alignment can ONLY come from tha datum, as that is what you have set as "master" (not ZERO, but "zero deviation from nominal").

    Aligned to datums, ANY and ALL dimensions COME FROM the datums.


    So if you have a 1-2-3 block with one hole in it 1 inch from each side and this CAD trihedron is 300 inches off in "X" and 200 inches in "Y" and I use an Iterative alignment, when I dimension my true position of said hole the nominals will be 1.00 inch each direction? Or will it be 301 inches and 201 inches.
Reply
  • Call it rude, call it whatever you want.

    You've been given ALL the (correct) answers, if you can't make heads or tails of it, then "chatting" on the webs won't solve it, you need classroom training.

    If you are aligned to the "A" datum (321 or iterative), any dimension created after the alignment can ONLY come from tha datum, as that is what you have set as "master" (not ZERO, but "zero deviation from nominal").

    Aligned to datums, ANY and ALL dimensions COME FROM the datums.


    So if you have a 1-2-3 block with one hole in it 1 inch from each side and this CAD trihedron is 300 inches off in "X" and 200 inches in "Y" and I use an Iterative alignment, when I dimension my true position of said hole the nominals will be 1.00 inch each direction? Or will it be 301 inches and 201 inches.
Children
No Data