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Iterative alignment and using XactMeasure

Alright here is my problem/question.
I have a part where Datum -A- (Z axis) is not prismatic, however datum -B- (X axis) and -C- (Y axis) are.

I do not have much experience with Iterative alignments other than that I have been to the Level 2 Hexagon class (Just don't use them or have the need too).

My thoughts were, this is a good time, to try an Iterative alignment.
I believe I have that part of the program correct:
I created 6 auto vector points on top (Datum -A-),
then 5 auto vector points on left side (Datum -B-)
then finally 5 auto vector points on the front of the part (Datum -C-).

When I create the Iterative alignment I pick top 6 points as level (Datum -A-),
5 points on left rotate (Datum -B-),
then 5 points on front as origin (Datum -C-).

After completing this Iterative alignment my trihedron doesn't move from before the alignment.
So I constructed planes out of the five points for datum -B- and -C- respectively.
I then origin my "X" to Datum -B- and my "Y" to datum -C-.
How do I origin my "Z", and how do I assign my datum -A- for exact measure? Where did I go wrong? Please any help would be greatly appreciated.
Parents
  • Yes, this was my original question/problem. How do you translate (origin) to my datum "A" for the Iterative alignment (if you can't determine the value), or define this irregular shape for Exactmeasure so that my dimensions for my true positions are the basic dimensions from the print. This is what my customer wants, and since the customer is always right, I came here for advice. It seems a lot of people want to give me answers not totally understanding what i'm up against. Maybe people jumped in before reading everything on this thread, I don't know. What I've done (I've stated this in a prior post) is put three auto vector points on approximately the three high spots of datum "A" (like if you set it down on a datum simulator surface i.e.surface plate) then constructed a plane out of those three points. Called that plane datum "A" and measured it in Exactmeasure. Voila, I didn't have to use an Iterative alignment, because that wouldn't work for my situation. I understand everything everyone is telling me, and I really do appreciate that,(except the few people that want to criticize and belittle people) I just don't think they understand what I'm telling them or trying to explain to them.Slight smile



    I'm sorry but I'm actually with everyone else on this one, what you've done isn't right.


    Quick question - before you do anything else if you select your B and C cylinders off the CAD are the vectors square to an axis? (0,0,1 or 1,0,0 etc)
Reply
  • Yes, this was my original question/problem. How do you translate (origin) to my datum "A" for the Iterative alignment (if you can't determine the value), or define this irregular shape for Exactmeasure so that my dimensions for my true positions are the basic dimensions from the print. This is what my customer wants, and since the customer is always right, I came here for advice. It seems a lot of people want to give me answers not totally understanding what i'm up against. Maybe people jumped in before reading everything on this thread, I don't know. What I've done (I've stated this in a prior post) is put three auto vector points on approximately the three high spots of datum "A" (like if you set it down on a datum simulator surface i.e.surface plate) then constructed a plane out of those three points. Called that plane datum "A" and measured it in Exactmeasure. Voila, I didn't have to use an Iterative alignment, because that wouldn't work for my situation. I understand everything everyone is telling me, and I really do appreciate that,(except the few people that want to criticize and belittle people) I just don't think they understand what I'm telling them or trying to explain to them.Slight smile



    I'm sorry but I'm actually with everyone else on this one, what you've done isn't right.


    Quick question - before you do anything else if you select your B and C cylinders off the CAD are the vectors square to an axis? (0,0,1 or 1,0,0 etc)
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