hexagon logo

Small arc method from Hexagon

A usual question about measuring small arcs, here the doc from Hexagon :
https://support.hexagonmi.com/s/article/How-to-measure-a-small-arc-less-than-90-degrees-1528360401117
  • So my question is how would you go about measuring something like what I have pictured? I have a way of doing it but I don't know if its right. Would the method above help with this when the radius and location are called out?
  • This is just an example, not a part I am working on now. Lets say its .375" since that is a common one for us.
  • OK, it's a little too large to consider a method from auto center point... Disappointed
  • This is how I do it.
    -Create an auto circle and use "to points"
    -Create an offset point using the constructed circle nominals
    -3d distance dimension from each of the points on the radius to the offset point, the nominal of the dimension should be the radius
    -Assign a variable adding the measured values and dividing by the number of dimensions (averaging)
    -Create a generic circle using loaction nominals from the offset point, vectors from the constructed circle, and set the measured radius as the variable above
    -Delete the constructed circle (won't be using that anymore)
    -Dimension to the generic circle

    It may not be the perfect answer but it is the best I've come up with. Doing this the distance dimensions actuals will change due to the radius of the generic circle changing. If I see any of the 3d dimensions (dimensions that are averaged to create the generic circle radius) go OOT, and I have confirmed with a radius gage that the radius is the correct size, I will know that the radius location is out and can analyze it from there. Say the above example is dimensioned in Y, I can move the arc hits and the constructed point either Y+ or Y- until I get a good radius.

    May not be the quickest way but it does work. I could use a loop command to move then retake the points until I get a good radius but I haven't had the need to yet.