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Measuring Point Profile from THEO and ACTL Values

Hello! First of all, I would like to mark that I am not experienced in operating CMM.

I wanted to check the coordinates of our measurement and thus required a detailed log of the process from the operator. I am assuming that THEO and ACTL values are theoretical and actual coordinates of the points. Also checked if my assumption is true on Nexus Hexagon docs.

Anyways, I started to calculate the distances between the THEO and ACTL coordinates. Then compared to the ones given as profiles on the report.

PNT11 =FEAT/CONTACT/VECTOR POINT/DEFAULT,CARTESIAN
THEO/<-4.524,21.406,-5.05>,<0.2517976,0.1223556,-0.9600141>
ACTL/<-4.529,21.41,-5.036>,<0.2517976,0.1223556,-0.9600141>
TARG/<-4.524,21.406,-5.05>,<0.2517976,0.1223556,-0.9600141>
SNAP=NO
SHOW FEATURE PARAMETERS=YES
SURFACE=THICKNESS_NONE,0
MEASURE MODE=NOMINALS
RMEAS=NONE,NONE,NONE
AUTO WRIST=NO
GRAPHICAL ANALYSIS=NO
FEATURE LOCATOR=NO,NO,""
SHOW CONTACT PARAMETERS=YES
AVOIDANCE MOVE=BOTH,DISTANCE=0
SHOW HITS=NO
MOVE/CLEARPLANE​




According to this calculation, i thought that my measurement should be off by 0.015 mm. However, as you can see below, the result was 0.019 mm off.




So, at this point i am curious how deviation is calculated by PC-DMIS. Can anyone care to explain?

Thanks in advance!
Parents

  • So with SNAP ON, when I test for coordinates, say (1,2,5) and the probe touches at coordinates (1.1, 2.1, 4.8), they will be snapped onto a point with the closest distance and on the x=1t, y=2t, z=5t vector. If I understood correctly, I assume deviation calculation is done as if the SNAP was ON behind the scenes. And actual coordinates fall onto a coordinate 0.19 mm away from theoretical ones, which is lying on x=-4.524t, y=21.406t, z=-5.05t vector.




    Thank you for wasting your time on a CMM illiterate. Smiley Having someone walking me through this stuff is great after brain-dead people working in my company.
Reply

  • So with SNAP ON, when I test for coordinates, say (1,2,5) and the probe touches at coordinates (1.1, 2.1, 4.8), they will be snapped onto a point with the closest distance and on the x=1t, y=2t, z=5t vector. If I understood correctly, I assume deviation calculation is done as if the SNAP was ON behind the scenes. And actual coordinates fall onto a coordinate 0.19 mm away from theoretical ones, which is lying on x=-4.524t, y=21.406t, z=-5.05t vector.




    Thank you for wasting your time on a CMM illiterate. Smiley Having someone walking me through this stuff is great after brain-dead people working in my company.
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