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Volume / Pressure Conversion

Robert Leach
All,

I know this is not necessarily PCDMIS related but it is job related.

The note on the print says:

Max leakage at 5.5 bar: 5 cubic mm per second at atmospheric pressure.

I have a tester that can input 80 psi and I can measure the drop in pressure. For instance I can watch for 1 min and see that it drops to 70psi. Is there a way to convert this into something I can use to satisfy the print callout? Any help would be greatly appreciated.
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  • The volume here is a confined space of compressed air, the same amount of air in a smaller space the greater the air pressure would be.

    No *****, and if you remove some of the mass of air within the smaller volume you can equate the 2 pressures meaning two different volumes at the same pressure.

    The escaped air has volume (space), since the pressure of compressed air is greater than atmospheric pressure, that air would expand until it reaches atmospheric pressure which is ~1 bar or ~14.5037738 psi a, equivalent to 0 psi g, depends on where you at. So, his question was; what is the actual cubic mm per second (volume/second) of escaped air at atmospheric pressure of 10psi/minute. which is impossible to answer.

    NO IT'S NOT. The ideal gas law will tell you the mass of escaped air. Using this mass you can then go back and recalculate for standard atmospheric conditions and find the volumetric flow rate. I am an engineer and this is very simple fluid dynamics. I have done these calculations many many times in the past. All he needs is the volume of the chamber he is pressurizing which should either be given or calculated, and if he has a CAD model then he can just get it off of there, and the state variables for the air.
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  • The volume here is a confined space of compressed air, the same amount of air in a smaller space the greater the air pressure would be.

    No *****, and if you remove some of the mass of air within the smaller volume you can equate the 2 pressures meaning two different volumes at the same pressure.

    The escaped air has volume (space), since the pressure of compressed air is greater than atmospheric pressure, that air would expand until it reaches atmospheric pressure which is ~1 bar or ~14.5037738 psi a, equivalent to 0 psi g, depends on where you at. So, his question was; what is the actual cubic mm per second (volume/second) of escaped air at atmospheric pressure of 10psi/minute. which is impossible to answer.

    NO IT'S NOT. The ideal gas law will tell you the mass of escaped air. Using this mass you can then go back and recalculate for standard atmospheric conditions and find the volumetric flow rate. I am an engineer and this is very simple fluid dynamics. I have done these calculations many many times in the past. All he needs is the volume of the chamber he is pressurizing which should either be given or calculated, and if he has a CAD model then he can just get it off of there, and the state variables for the air.
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