hexagon logo

Slope of lines: Created from points at Basic Diameters

Team,

I'm having trouble with Slope of lines created from points at Basic diameters. The picture shows 4 points ( E,F,G AND H ) all located on Basic diameters. The slope call out appears to be asking slope of each line to Datum -A-, which is the top plane, Z axis of part. I have taken these points at the specified basic diameters, created lines from these points, but the results are 0.297 inches. I know I'm doing something wrong.
Any help is appreciated. Will provide more info if needed.
Greg.




Slope issue picture.pdf
Parents

  • YE instead of XE in YF !!!!!
    I'm a little confuse because my calculations of YF doesn't match with values Disappointed (4.192 instead of 4.235) - and I believe that values are right !

    Polar angles, something like this :
    ASSIGN/XE=-2.635/2
    ASSIGN/RE=7.260/2
    ASSIGN/POLAR_E=RAD2DEG(ACOS(XE/RE))
    ASSIGN/YE=RE*SIN(DEG2RAD(POLAR_E))
    ASSIGN/RF=8.88/2
    ASSIGN/XF=XE-(RF-RE)*SIN(DEG2RAD(1))
    ASSIGN/YF=[COLOR=#ff0000]YE[/COLOR]+(RF-RE)*COS(DEG2RAD(1))
    ASSIGN/POLAR_F=RAD2DEG(ATAN(YF/XF))


    maybe :
    polar_e=111.281
    polar_f=103.411​


Reply

  • YE instead of XE in YF !!!!!
    I'm a little confuse because my calculations of YF doesn't match with values Disappointed (4.192 instead of 4.235) - and I believe that values are right !

    Polar angles, something like this :
    ASSIGN/XE=-2.635/2
    ASSIGN/RE=7.260/2
    ASSIGN/POLAR_E=RAD2DEG(ACOS(XE/RE))
    ASSIGN/YE=RE*SIN(DEG2RAD(POLAR_E))
    ASSIGN/RF=8.88/2
    ASSIGN/XF=XE-(RF-RE)*SIN(DEG2RAD(1))
    ASSIGN/YF=[COLOR=#ff0000]YE[/COLOR]+(RF-RE)*COS(DEG2RAD(1))
    ASSIGN/POLAR_F=RAD2DEG(ATAN(YF/XF))


    maybe :
    polar_e=111.281
    polar_f=103.411​


Children
No Data