Slope of lines: Created from points at Basic Diameters

Team,

I'm having trouble with Slope of lines created from points at Basic diameters. The picture shows 4 points ( E,F,G AND H ) all located on Basic diameters. The slope call out appears to be asking slope of each line to Datum -A-, which is the top plane, Z axis of part. I have taken these points at the specified basic diameters, created lines from these points, but the results are 0.297 inches. I know I'm doing something wrong.
Any help is appreciated. Will provide more info if needed.
Greg.

Slope issue picture.pdf

Parents

JEFMAN over 2 years ago

Got it !
The distance between G and H isn't the difference of radii !!!!!!!

ASSIGN/XE=-2.635/2
ASSIGN/RE=7.260/2
ASSIGN/POLAR_E=RAD2DEG(ACOS(XE/RE))
ASSIGN/YE=RE*SIN(DEG2RAD(POLAR_E))
ASSIGN/RF=8.88/2
ASSIGN/POLAR_H=RAD2DEG(ACOS(-XE/RF))
ASSIGN/YH=RF*SIN(DEG2RAD(POLAR_H))
ASSIGN/XF=XE-(YH-YE)*SIN(DEG2RAD(1))
ASSIGN/YF=SQRT(RF^2-XF^2)
ASSIGN/POLAR_F=RAD2DEG(ATAN(YF/XF))
ASSIGN/VECTOR_EF=UNIT(MPOINT(XF-XE,YF-YE,0))

Thx vpt.se to share right values !!!!!!!

Reply

JEFMAN over 2 years ago

Got it !
The distance between G and H isn't the difference of radii !!!!!!!

ASSIGN/XE=-2.635/2
ASSIGN/RE=7.260/2
ASSIGN/POLAR_E=RAD2DEG(ACOS(XE/RE))
ASSIGN/YE=RE*SIN(DEG2RAD(POLAR_E))
ASSIGN/RF=8.88/2
ASSIGN/POLAR_H=RAD2DEG(ACOS(-XE/RF))
ASSIGN/YH=RF*SIN(DEG2RAD(POLAR_H))
ASSIGN/XF=XE-(YH-YE)*SIN(DEG2RAD(1))
ASSIGN/YF=SQRT(RF^2-XF^2)
ASSIGN/POLAR_F=RAD2DEG(ATAN(YF/XF))
ASSIGN/VECTOR_EF=UNIT(MPOINT(XF-XE,YF-YE,0))

Thx vpt.se to share right values !!!!!!!

Children

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