In a polar coordinate system (r, θ), the position error is calculated as 2*sqrt(r^2 + (r0)^2 - 2*r*r0*cos(Δθ)) where r is the measured radial distance, r0 is the nominal radial distance, and Δθ is the difference between the measured and the nominal angle.
In a Cartesian coordinate system (x, y), the position error is calculated as 2*sqrt((Δx)^2 + (Δy)^2) where Δx and Δy are the deviations from nominal in the X and Y axes, respectively.
A short cut that will get you close BUT NOT DEAD ON ACCURATE, when you don't have a calculator handy, Take the higher number of the 2 direction X or Y doesn't matter. This is stuff you can do in your head.
Example: Let's say X is .0032 out from 0, and Y is .0012
So take your X times it by 2 =.0064, because it's the higher number of the 2, take your Y cut in half .0006 add it together .0064+.0006=.007 <<<<Position
Now using the correct formula as stated above your position is actually .006835
MetsoMetrology oops somebody was talking to me when I was typing. was supposed to be .0032 . Fat fingered it. and fixed it above. The Position number is still correct. Just dyslexic moment.
A short cut that will get you close BUT NOT DEAD ON ACCURATE, when you don't have a calculator handy, Take the higher number of the 2 direction X or Y doesn't matter. This is stuff you can do in your head.
Example: Let's say X is .0032 is out from 0, and Y is .0012 So take your X times it by 2 =.0064, because it's the higher number of the 2, take your Y cut in half .0006 add it together .0064+.0006=.007 <<<<Position Now using the correct formula as stated above your position is actually .006835
Since I did have a Dyslexic moment as
MetsoMetrology pointed out. lets say X is .0023 and Y .0012
X doubled =.0046 + half of Y is .0006 = "(.0046 + .0006 = .0052)"
With the true formula comes out .005188
