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code for checking an exception

jigars
Need to calculate these from a set of 8 results
[Spacing error not to exceed 0.005,
spacing between adjacent slot 0.003, 1 place may be 0.005 max]
I am using following code to calculate spacing error within 0.005, but I'm not sure how to find " 1 place may be 0.005 max"
I would highly appreciate any guidance as I need to create similar program for 60 set of slots as well.

LOC_ADJ1, 2, 3... is the spacing between adjacent slots

ASSIGN/ZERO=0

ASSIGN/V1=LOC_ADJ1.X.MEAS
ASSIGN/V2=LOC_ADJ2.X.MEAS
ASSIGN/V3=LOC_ADJ3.X.MEAS
ASSIGN/V4=LOC_ADJ4.X.MEAS
ASSIGN/V5=LOC_ADJ5.X.MEAS
ASSIGN/V6=LOC_ADJ6.X.MEAS
ASSIGN/V7=LOC_ADJ7.X.MEAS
ASSIGN/V8=LOC_ADJ8.X.MEAS

ASSIGN/VR=ARRAY(V1,V2,V3,V4,V5,V6,V7,V8)
ASSIGN/VMAX=MAX(VR)
ASSIGN/VMIN=MIN(VR)
ASSIGN/AVG=VMAX-VMIN

F1 =GENERIC/POINT,DEPENDENT,CARTESIAN,$
NOM/XYZ,<ZERO,ZERO,ZERO>,$
MEAS/XYZ,<AVG,AVG,AVG>,$
NOM/IJK,<0,0,1>,$
MEAS/IJK,<0,0,1>

DIM LOC_ADJ9= LOCATION OF POINT F1 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH HALF ANGLE=NO
AX NOMINAL +TOL -TOL MEAS DEV OUTTOL
X 0.00000 0.00500 0.00500 0.00001 0.00001 0.00000 --#--
END OF DIMENSION LOC_ADJ9
  • hello there,

    I don't quite understand your question, but you want to know whether more than one measurement result is greater than or equal to 0.005?

    "MAXINDICES" sorts an array according to size. In this sorted array, the two largest values ​​should not exceed 0.003. but only the 1st
    Maybe that will help. 


    ASSIGN/V1=ARRAY(0.002,0.003,0.005)
ASSIGN/V2=MAXINDICES(V1)

IF/(V1[V2[1]] > 0.003) AND (V1[V2[2]] > 0.003)
  $$ NO,
  more than one measurement result is greater than 0.003
END_IF/

IF/(V1[V2[1]] > 0.003) AND (V1[V2[2]] <= 0.003)
  $$ NO,
  only one measurement result is greater than 0.003
END_IF/

IF/V1[V2[1]] <= 0.003
  $$ NO,
  no measurement result is greater than 0.003
END_IF/
  • Not sure to understand what you want...
    I would :
    Create a feature set with all the slots (SCN1)
    Then, I would calculate the deviations along X axis in two arrays:
    ASSIGN/V1=SCN1.HIT[1..(SCN1.NUMHITS-1)].X-SCN1.HIT[1..(SCN1.NUMHITS-1)].TX
    ASSIGN/V2=SCN1.HIT[2..(SCN1.NUMHITS)].X-SCN1.HIT[2..(SCN1.NUMHITS)].TX
    Then, I would subtract V2 to V1 to get the error spacing, and calculate the absolute value, to take into account the case of a spacing lower than -0.005 :
    ASSIGN/ERROR_SP=ABS(V2-V1)
    Then, I would search how many values are >= 0.005 :
    ASSIGN/SEARCH_DEFECT=SUM(INT(ERROR_SP/0.005))
    Then, it depends on what you have to decide...
    Something like :
    IF/(SEARCH_DEFECT>1) OR (MAX(ERROR_SP)>0.005)
    COMMNENT/OPERATOR
    THE PART IS OOT
    END IF

  • in reply to Henniger123
    Hi Henniger123,
    Thanks for replying, this should do.
    But there 8 values that needs to be considered, can i use the same code for 8 values?
  • in reply to JEFMAN
    To simplify my question
    Lets say there are 8 holes with dia d1, d2, ... d8
    7 dia should be within +/- 0.003
    only one dia is allowed within +/- 0.005 (it can be any of 8 dia)
  • With diameter example (all the holes in SCN1): 

    ASSIGN/V1=SCN1.HIT[1..SCN1.NUMHITS].D-SCN1.HIT[1..SCN1.NUMHITS].TD
ASSIGN/V2=ABS(V1)
ASSIGN/V3=((0.003-V2)-ABS(0.003-V2))/((0.003-V2)-ABS(0.003-V2))
IF/(SUM(V3)>1) OR (MAX(V2)>0.005)
COMMNENT/OPERATOR
THE PART IS OOT
END IF


    V1 is an array of diameter deviations, V2 is the absolute dev.
    V3 is an array of 0 and 1 (1 for each deviation >0.003)
    Hope this helps...
  • Yeah, I'm a bit confused as well. Your code shows you are assessing the average. why? your spec says nothing about average.
    If your spec is exclusively only concerning the variation of X axis, relative to adjacent features, you should assess the distance between each feature, then summarize max and min of all of them... No reason for averaging them out.

    If what you are "simplifying" is accurate, has a rock-solid method.

  • in reference to Post#3.1

    this should be close to what you're looking for 

    
DIM LOC1= LOCATION OF CIRCLE CIR1 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 1.00100 1.00000 0.00300 0.00300 0.00100 0.00000 -----#---
END OF DIMENSION LOC1
DIM LOC2= LOCATION OF CIRCLE CIR2 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 1.00200 1.00000 0.00300 0.00300 0.00200 0.00000 -------#-
END OF DIMENSION LOC2
DIM LOC3= LOCATION OF CIRCLE CIR3 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 0.99900 1.00000 0.00300 0.00300 -0.00100 0.00000 --#------
END OF DIMENSION LOC3
DIM LOC4= LOCATION OF CIRCLE CIR4 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 0.99700 1.00000 0.00300 0.00300 -0.00300 0.00000 #--------
END OF DIMENSION LOC4
DIM LOC5= LOCATION OF CIRCLE CIR5 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 0.99600 1.00000 0.00300 0.00300 -0.00400 0.00100 <--------
END OF DIMENSION LOC5
DIM LOC6= LOCATION OF CIRCLE CIR6 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 0.99800 1.00000 0.00300 0.00300 -0.00200 0.00000 -#-------
END OF DIMENSION LOC6
DIM LOC7= LOCATION OF CIRCLE CIR7 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 0.99700 1.00000 0.00300 0.00300 -0.00300 0.00000 #--------
END OF DIMENSION LOC7
DIM LOC8= LOCATION OF CIRCLE CIR8 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=NONE HALF ANGLE=YES
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
D 1.00300 1.00000 0.00300 0.00300 0.00300 0.00000 --------#
END OF DIMENSION LOC8
ASSIGN/V1=ARRAY(LOC1.D.DEV,LOC2.D.DEV,LOC3.D.DEV,LOC4.D.D EV,LOC5.D.DEV,LOC6.D.DEV,LOC7.D.DEV,LOC8.D.DEV)
ASSIGN/V2=SORTDOWN(ABS(V1))
IF/V2[1]>0.005
COMMENT/OPER,NO,FULL SCREEN=NO,AUTO-CONTINUE=NO,OVC=NO,
WORST PART OUT OF THE EIGHT HAS DEVIATION EXCEEDING ±0.005 !!!
END_IF/
IF/V2[2]>0.003 OR V2[3]>0.003 OR V2[4]>0.003 OR V2[5]>0.003 OR V2[6]>0.003 OR V2[7]>0.003 OR V2[8]>0.003
COMMENT/OPER,NO,FULL SCREEN=NO,AUTO-CONTINUE=NO,OVC=NO,
ONE OR MORE OF THE REMAINING CIRCLES HAVE DEVIATION EXCEEDING ± 0.003!!!
END_IF/


    -report them all out (output NONE)
    -list them in an array (list of the DEVIATIONS FROM NOMINAL)
    -sort the array so we get the ABSOLUTE VALUES sorted from highest to lowest
    -check that position 1 is less than 0.005
    -check that positions 2-8 are less than 0.003
    -set up comments or something to show this information

  • If your spec is exclusively only concerning the variation of X axis, relative to adjacent features, you should assess the distance between each feature, then summarize max and min of all of them... No reason for averaging them out.

    That's why I assigned the difference of deviations, without dimensionning distances if there are not usefull in a report (it takes a lot of place in the prog, so it's less readable...)



    If what you are "simplifying" is accurate, has a rock-solid method.
    Thanks, Rolling eyes

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