hexagon logo
Register Sign in
  • Replies 7 replies
  • Subscribers 221 subscribers
  • Views 234 views
  • Users 0 members are here
Options
Related

find intersection of a generic circle and angled plane below the surface

joedraper
Hi all, I am new to PC-DMIS (2021R1 CAD++) and have been working on trying to configure a measurement for a couple weeks now. I do apologize for my terminology ahead of time. This forum has helped tremendously with the other measurements for this part, however, I have not been able to find a post related to this special characteristic that can apply to what I am looking to accomplish.

I am looking for some advice regarding a special characteristic that I need to find the intersection measurement between a generic circle/cylinder (R=34.5) and -0.49 below the part surface on an angled plane of 10+/-0.5 deg from the center of the measured circle (R= 30.25). The whole part is in 3D space, but the SC i am looking for is shown in 2D (ZX) as a side view. (hopefully the pic is visible). ​ ​
​ ​
Ive experimented with different settings/methods for constructing lines, points, planes and generic constructions of cylinders/circles to try and program the needed measurement efficiently and accurately. I may be missing a step when trying to align the generic circle (34.5R @ Z-PLUS) to the smaller measured circle (which R=30.25) located below the angled plane. Another issue i have encountered is trying to create a stationary line from the center of the constructed circle intersecting at the desired measurement location (generic circle and angled plane intersection), in tolerance (0.49 +0.08/-0.02).

Please let me know if additional clarification. I am very grateful for any help and direction from the community Slight smile . Thanks in advance!

  • Hello,
    I'm not sure if I understood that correctly.
    But can you try to interpret this problem as in the drawing. Wish is in 2D.

    I mean replacing the two circle/cylinder with two lines pointing to ZPlus.
    With these lines you should be able to create an intersection point in the angled plane.

    I can't tell which align to choose because the drawing is incomplete
  • Yes, i can interpret it in 2D.
    So, the special characteristic i am looking for is located on the angled plane 4.25 units in the X direction from the left edge (where the end of the smaller circle is located) and 0.49 below the parts surface.

    I created a cylinder with R=34.5 (with the same origin as the smaller circle) with an intersecting line at -0.49 below the surface. At that intersection, i created a pierce point to identify the intersection on the angled plane.
    I could have very well overcomplicated this when trying to create the program for the 3D part, which is why i reached out to the forum.
  • would you like to post a little more of the drawing,
    maybe a top view (zplus) ?
  • Create line on angled plane.
    Create pierce point by intersecting the line and the cylinder you have created with R34.5.
    Dimension the 0.49 to the pierce point.
    Profit.

    Don't use the 0.49 at all. That's the dimension you are looking for. The cylinder sets the rules @ [34.5]. The point where the angled line pierces the cylinder should be 0.49 ± tol from the plane.
  • I would :
    Create the cylinder R 34.5 - Level Z on it - CYL1
    Measure the 10° plane - PL1, crreate the pierce pointe CYL1/PL1 - (PT1)
    ASSIGN/V1=CROSS(CYL1.IJK,CROSS(PL1.IJK,CYL1.IJK))
    Create a generic line with CYL1.XYZ and V1.IJK
    Create an alignment CYL1 Level Z, rotation X generic line, origin PT1.
    Create another generic line with <±34.5,0,0> and <0,0,1> (depends on the direction of V1 !)
    Create the pierce point between this line and PL1
    Dimension this point from upper plane.
  • in reply to vpt.se
    How would I create the line centered on the angled plane? I created a line which got me the correct value after playing around with the line methods but the line is not on the correct angled plane(line is below the part but at the correct angle) even though the point is at the correct placement. Here is the code i used (also included an angled dimension check for line8):

    GF_CYL34.5R=GENERIC/CYLINDER,DEPENDENT,CARTESIAN,OUT,$
    NOM/XYZ,<0,0,0>,$
    MEAS/XYZ,<-150,-54,-0.57>,$
    NOM/IJK,<0,0,1>,$
    MEAS/IJK,<0,0,1>,$
    RADIUS/0,34.5,$
    DISTANCE/0,0.1

    LIN5 =FEAT/LINE,CARTESIAN,UNBOUNDED,YES
    THEO/<-150,-54,-0.49>,<1,0,0>
    ACTL/<-149.01,-54.002,-6.47>,<0.9847854,-0.0017986,0.1737654>
    CONSTR/LINE,PROJ,ANG_PLN_F,GF_CYL34.5R,50

    LIN8 =FEAT/LINE,CARTESIAN,UNBOUNDED,NO
    THEO/<-100,-54,-0.49>,<-1,0,0>
    ACTL/<-148.911,-54.002,-6.453>,<-0.9847854,0.0017986,-0.1737654>
    CONSTR/LINE,REV,LIN5,50

    PNT_PIERCE_W_LIN8=FEAT/POINT,CARTESIAN,NO
    THEO/<0,0,0>,<0,0,1>
    ACTL/<-115.5,-54.063,-0.557>,<-0.9847854,0.0017986,-0.1737654>
    CONSTR/POINT,PIERCE,LIN8,GF_CYL34.5R

    DIM ANGL10 CHECK FOR LINE8= 3D ANGLE FROM LINE LIN8 TO XAXIS ,$
    GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH
    AX NOMINAL MEAS +TOL -TOL DEV OUTTOL
    A 10.000 10.007 0.500 0.500 0.007 0.000 --#-

    DIM DIST_PNT2_PIERCE= 3D DISTANCE FROM PLANE PLN2_FOR_SC TO POINT
    PNT_PIERCE_W_LIN8,SHORTEST=ON,NO_RADIUS UNITS=MM,$
    GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH
    AX NOMINAL MEAS +TOL -TOL DEV OUTTOL
    M 0.490 0.542 0.080 0.020 0.052 0.000 --#-
  • in reply to vpt.se
    Use two auto vector points (having CAD is VERY helpful). Let's go by the orientation of the snippet you posted.

    Take the first vector point at the low end of the angled plane.
    Take a second vector point at the higher end of the angled plane.
    Create a 3D line between the first vector point to the second vector point (line direction is now left-to-right).
    *3D line because typing the creation of a 2D line is just too much to type...
    Create a pierce point using the line and your cylinder. This point should end up close to the high end of the plane.
    If it doesn't, construct a new line using the line you already created, but flip the direction of it (reverse).
    Then try to pierce the cylinder with the new line and see if it ends up at the high end.
    Dimension accordingly.
© 2024 Hexagon AB and/or its subsidiaries. Privacy Policy | Cloud Services Agreement