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How / Can You Amend Out Of Tolerance Hole Size in 2022.1

Inspectorl9
Scenario : For a FAIR you measure a part and a hole diameter is found to have measured out of tolerance.
You measure the hole by an alternative method , is a bore micrometer and find it falls within the tolerance range.
in version 2020R1 you are able to amend the measured value so it falls within the tolerance range.

We have found that in the latest version of 2022.1 you are unable to do this.

Any suggestions going forward as our QM will not accept FAIR with out of tolerance results.

Are we to be stuck using 2020R1 forever??
Parents
  • An option could be to have an input box appear if the feature measures o/tol on cmm to input the manually evaluated value. Then, using assignments, pass the location information through a generic circle and use the input value for the size. Something like: 
    ASSIGN/DIA_SIZE=CIR_62.D
IF/CIR_62.D>2.8885 OR CIR_62.D<2.8875
PLAN1 =COMMENT/INPUT,NO,FULL SCREEN=NO,
Enter diameter size from manual evaluation
ASSIGN/DIA_SIZE=PLAN1.INPUT
END_IF/
F5 =GENERIC/CIRCLE,DEPENDENT,CARTESIAN,OUT,$
NOM/XYZ,<CIR_62.TX,CIR_62.TY,CIR_62.TZ>,$
MEAS/XYZ,<CIR_62.X,CIR_62.Y,CIR_62.Z>,$
NOM/IJK,<CIR_62.TI,CIR_62.TJ,CIR_62.TK>,$
MEAS/IJK,<CIR_62.I,CIR_62.J,CIR_62.K>,$
DIAMETER/2.888+0,DIA_SIZE
DIM DIM1= LOCATION OF CIRCLE F5 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH HALF ANGLE=NO
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
X 0.0000 0.0000 0.0020 0.0020 0.0000 0.0000 -#--
Y 31.8800 31.8800 0.0020 0.0020 0.0000 0.0000 -#--
Z 0.0000 0.0000 0.0020 0.0020 0.0000 0.0000 -#--
D 2.8876 2.8880 0.0005 0.0005 -0.0004 0.0000 #---
END OF DIMENSION DIM1


    As a work around on a FAIR...this is the way

    From the other area...
Reply
  • An option could be to have an input box appear if the feature measures o/tol on cmm to input the manually evaluated value. Then, using assignments, pass the location information through a generic circle and use the input value for the size. Something like: 
    ASSIGN/DIA_SIZE=CIR_62.D
IF/CIR_62.D>2.8885 OR CIR_62.D<2.8875
PLAN1 =COMMENT/INPUT,NO,FULL SCREEN=NO,
Enter diameter size from manual evaluation
ASSIGN/DIA_SIZE=PLAN1.INPUT
END_IF/
F5 =GENERIC/CIRCLE,DEPENDENT,CARTESIAN,OUT,$
NOM/XYZ,<CIR_62.TX,CIR_62.TY,CIR_62.TZ>,$
MEAS/XYZ,<CIR_62.X,CIR_62.Y,CIR_62.Z>,$
NOM/IJK,<CIR_62.TI,CIR_62.TJ,CIR_62.TK>,$
MEAS/IJK,<CIR_62.I,CIR_62.J,CIR_62.K>,$
DIAMETER/2.888+0,DIA_SIZE
DIM DIM1= LOCATION OF CIRCLE F5 UNITS=IN ,$
GRAPH=OFF TEXT=OFF MULT=10.00 OUTPUT=BOTH HALF ANGLE=NO
AX MEAS NOMINAL +TOL -TOL DEV OUTTOL
X 0.0000 0.0000 0.0020 0.0020 0.0000 0.0000 -#--
Y 31.8800 31.8800 0.0020 0.0020 0.0000 0.0000 -#--
Z 0.0000 0.0000 0.0020 0.0020 0.0000 0.0000 -#--
D 2.8876 2.8880 0.0005 0.0005 -0.0004 0.0000 #---
END OF DIMENSION DIM1


    As a work around on a FAIR...this is the way

    From the other area...
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