Is it possible to construct a point here?

If you are looking to output the 6.6 distance you can output a distance using add radius.

If you are looking to output the 6.6 distance you can output a distance using add radius.

I got that one, I'm looking to get the 63.7 dimension. This print seems to be for building a cad and not for tolerancing, but here I am.

Construct an intersection from both radius or line to radius intersection.

Construct an intersection from both radius or line to radius intersection.

Here's what I got, please explain a little more in depth.

where you have lin19 measure that radius to the left from that feature then measure cir4 a little bit more then construct a point of intersection between those 2 radius. if it falls short then just subtract intersect # & the 63.7 basic number from the print, add that number offset to the calculated number from the intersection point to where it should be and dimension that result

same thing with the 77.9 basic...

Print looks to have a straight surface before the intersection. Intersection point using a tiny line with the circle shouldn't be a problem.

If the R11.5 and rad marked just R are perfect blends with no small flat between them you could try the this.

1; Measure both radius.
2: Construct a Line between the 2 radius.
3: Construct a point from the line to one of the radius to create the Tangent point you may have to reverse the line to get correct point.
4: Set a new alignment rotated to the constructed line and origin set X,Y on the constructed point.
5: Construct a generic line X,Y 0,0, set the line vector to produce a line perpendicular to the first constructed line.
6: recall the original alignment.
7 Construct a generic line with Y values CIR4.Y+CIR4.R for both NOM and MEAS. Set the line vector as 1,0,0
8 Construct a point by intersection of the 2 Generic lines and dimension.

If there is a small flat no perfect blend just measure that and intersect with the second generic line in above example.

UKCMM 's solution with assignments (assuming that the top plane is Z+, LIN18 X+ from left to right, ALN is the current alignment) :

Then intersect F1 and F2​
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