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True position of sphere

Hello! i'm new to this forum and only have cad lvl2 training. i'm insectiing the simple part, 11.7mm diameter cylinder with tapering spherical tip that has a diameter of 1.3mm. cylinder is datum A and the flat face of the cylinder is datum B.

 How does the software calculate the TP of the sphere? How does the 69.350 dimension(distance from datum B) come into this calculation?
Any explanation is really appriciated.

Thank you

Yoahn P
Parents
  • {"data-align":"none","data-size":"full","data-tempid":"temp_24979_1690204598879_917","title":"alignment.jpg"}{"data-align":"none","data-size":"full","data-tempid":"temp_24980_1690204640294_120","title":"sphere.jpg"}​Hi! here are the snips of the code. My main question is how did the software calculate the true position to .017 to A|B. if i use the formula, it should be around .400. This morning, I switch the workplane to Y and got the true position as .414. does that mean, i was wrong the first time by inspecting it in the Z plus workplane?

    Thank you .

Reply
  • {"data-align":"none","data-size":"full","data-tempid":"temp_24979_1690204598879_917","title":"alignment.jpg"}{"data-align":"none","data-size":"full","data-tempid":"temp_24980_1690204640294_120","title":"sphere.jpg"}​Hi! here are the snips of the code. My main question is how did the software calculate the true position to .017 to A|B. if i use the formula, it should be around .400. This morning, I switch the workplane to Y and got the true position as .414. does that mean, i was wrong the first time by inspecting it in the Z plus workplane?

    Thank you .

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