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alignment question on Romer

Clementine
I am trying to align a part on our Romer and the print is not the greatest in geometric callouts. Please review attached print.
I have 3 cylinders as Datums. I have not aligned a part using all cylinders and would appreciate help. Print is difficult.

I have the A datum facing up in the Z axis on the table.

I am thinking I need to create an origin for X and Y at the intersection of A and C. and call that a different datum. I am thinking the alignment would be.


Level: A +/-X,Y, or Z Zplus

Rotate: C +/-X,Y, or Z X plus

Origins:
X: c

Y: c

Z: A


Thank you for advice.
Attached Files
  • I would do a cylinder - cylinder alignment to Datums A and C.

    Basically, Level z to A
    Rotate to C
    Datum A is the xy origin
    datum C is the z origin
  • Colin,

    I almost had it.... Below is my understanding of your suggested alignment. Just had a question on the rotation to X plus. Please confirm if X plus is the right direction. After studying print, I am thinking the direction could be X minus instead. What do you think?
    So I do not need to make a point for the origin. The system will know that is the origin point, right?

    Level: cyl A to Z plus

    Rotate: cyl C to X plus??

    Origins:
    X: A
    Y: A
    Z: C
  • Colin,

    I almost had it.... Below is my understanding of your suggested alignment. Just had a question on the rotation to X plus. Please confirm if X plus is the right direction. After studying print, I am thinking the direction could be X minus instead. What do you think?
    So I do not need to make a point for the origin. The system will know that is the origin point, right?

    Level: cyl A to Z plus

    Rotate: cyl C to X plus??

    Origins:
    X: A
    Y: A
    Z: C

    I can't answer that question, because it is dependent on the way you created the cylinder. A cylinder's direction is dependent on the way you created it. It might be bottom-to-top or top-to-bottom. So....I can't answer the "what direction do I rotate/level to" part of the question.

    As to the second part, no, you don't need to create a point. You've set the origin at the X value of the A, the Y value of the A, and the Z value of the C. It's the same thing as setting the origin at the XYZ of a single point entity, you've just used separate entities called cylinders to do so.
  • I would create cyl A from the bottom ID to the top ID have the Z axis vertex going upward.
    I would also create cyl C from the base of the flange OD to the top OD edge. The cyl C would be facing the X minus direction.
    Did I answer my own question?

    So the rotate would be Cyl C rotate Xminus. Right?????
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