Please excuse my ignorance. Straight of the bat i am a quality op who has been side tracked into CMM work and on a very steep learning curve. Have working knowledge of dmis but not in anyway proficient. Now to my silly question. I have attached a image of the dim i am after. I am working n a OPTIV 321 WITH DMIS 2014_1. I have the diameter of the cir ok, but how do i get intersecting lines from the legs to pick up the 4.81 dim.
. Thanks in advance and forgive my ignorance.
Bluenowhere
I am assuming you are using vision. My apologies however I cannot see the dimension you are after as I cannot see your image, the resolution is very small. Would you mind adding a different image that is larger and what you are trying to achieve with a little more detail.
Hope this works better....basically how can i get the 4.81 dim as required do i need to project a line from the circle or what complete dummy here folks flying by the seat of my pants in CMM land. Ps using vision but can probe if nessecary
I'm not at the cmm, but I think you can dimension the distance between line and circle, with the option "add radius" or something like this.
You can also do it with an assignment ASSIGN/V1=DIST1.MEAS + CIRC1.R (here, dist1.meas is the distance between the center of the circle and the line)
The first part though finding the top of that circle. I have never used the add radius as JEFMAN suggested. If you do the following however you should find the top of that circle pretty easily.
-Probe or Vision the Circle simply as a circle.
-Note the center location of the circle.
-Probe or Vision another point at the same X location (
Do this by an Auto Point or by Probing anywhere near the point and then adjusting the X location) as the center of the circle but add the Radius of the Circle to the Y part of the location you got for center. This will give you the same X center but you will probe towards the top edge of the circle by adding the radius to the Y location of the point.
This should give you the top of the circle at its peak Y and Center X location.
IF the dimension references to the center where the two angles meet that makes it easy. Now that I am looking at it I believe this is the case.
-Simply Probe or Vision the two angles as lines
-Construct an Intersection Point between the two lines. (
When you construct a point there will be a drop down menu to choose which type of point)
Then simply dimension Distance from your Point on the Circle and your Intersection Point.
. Thanks in advance and forgive my ignorance.
